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in execcises 1-6 write the next three terms of the arithmetic sequence. 1. 1,8,15,22,ldots 2. 20,14,8,2,ldots 3. 12,21,30,39,ldots 4.

Question

In Execcises 1-6 write the next three terms of the arithmetic sequence. 1. 1,8,15,22,ldots 2. 20,14,8,2,ldots 3. 12,21,30,39,ldots 4. 5,12,19,26,ldots 5. 3,7,11,15,ldots 6. 2,14,26,38,ldots

Solution

Verificación de expertos
4 (282 Votos)
Vinícius Mestre · Tutor por 5 anos

Resposta

1. To find the next three terms of the arithmetic sequence , we need to determine the common difference between consecutive terms. The common difference is . To find the next term, we add the common difference to the last term: . To find the term after that, we add the common difference again: . Therefore, the next three terms of the sequence are . 2. To find the next three terms of the arithmetic sequence , we need to determine the common difference between consecutive terms. The common difference is . To find the next term, we add the common difference to the last term: . To find the term after that, we add the common difference again: . Therefore, the next three terms of the sequence are . 3. To find the next three terms of the arithmetic sequence , we need to determine the common difference between consecutive terms. The common difference is . the next term, we add the common difference to the last term: . To find the term after that, we add the common difference again: . Therefore, the next three terms of the sequence are . 4. To find the next three terms of the arithmetic sequence , we need to determine the common difference between consecutive terms. The common difference is . To find the next term, we add the common difference to the last term: . To find the term after that, we add the common difference again: 33, 40, 47 3,7,11,15,\ldots 7 - 3 = 4 15 + 4 = 19 19 + 4 = 23 19, 23, 27 226,38,\ldots 14 - 2 = 12 38 + 12 = 50 50 + 12 = 62 50, 62, 74$.