4x Write an equation of the line that is parallel to 5x+20y=10 and passes through the point (8,3) A y=4x-29 B y=4x+35 C y=(1)/(4)x-1 D y=-(1)/(4)x+3 E y=-(1)/(4)x+5

## Step 1The given equation of the line is . We need to convert this equation into the slope-intercept form, which is , where is the slope of the line and is the y-intercept.## Step 2To convert the given equation into slope-intercept form, we divide the entire equation by 20. This gives us .## Step 3The slope of the given line is . Since parallel lines have the same slope, the slope of the line we are looking for is also .## Step 4We are given a point (8,3) that lies on the line we are looking for. We can use the point-slope form of a line equation, which is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and is the slope.## Step 5Substituting the given point and slope into the point-slope form gives us \(y - 3 = -\frac{1}{4}(x - 8)\).## Step 6Solving this equation for gives us the equation of the line in slope-intercept form: .