Question
Solve each by using the quadratic formula. 1 5x^2+21x=-18 2 81x^2=9 3 8x^2+12x=8 4 4x^2=-16x-16 5 10x^2=-7x+6 6 -3x^2=8x-12 7 2x^2=12x-18 8 -3x^2=12-12x 9 0.2x^2-1.5x+2.9=0 10 2x^2-5x=-20 State the discriminant for each equation. Then determine the number of real solutions of the equation. 11 0.2x^2-1.5x+2.9=0 12 2.25x^2-3x=-1 13 x^2-(4)/(5)x=3 14 0.5x^2-2x=-2 15 2x^2=(5)/(2)x+(3)/(2)
Solution
4.4
(242 Votos)
Leidi
Mestre · Tutor por 5 anos
Resposta
Let's solve each quadratic equation using the quadratic formula and then state the discriminant for each equation to determine the number of real solutions.### Solving Quadratic Equations Using the Quadratic FormulaThe quadratic formula is given by:
where
.#### 1.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is positive, there are two real solutions.#### 2.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is positive, there are two real solutions.#### 3.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is positive, there are two real solutions.#### 4.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is zero, there is one real solution.#### 5.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is positive, there are two real solutions.#### 6.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is positive, there are two real solutions.#### 7.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discriminant:
Since the discriminant is zero, there is one real solution.#### 8.
Rewrite the equation in standard form:
Here,
,
, and
.Calculate the discrimin