Misaka solved the radical equation x-3=sqrt (4x-7) but did not check her solutions (x-3)^2=(sqrt (4x-7))^2 x^2-6x+9=4x-7 x^2-10x+16=0 (x-2)(x-8)=0 x=2 and x=8 Which shows the true solution(s) to the radical equation x-3=sqrt (4x-7) x=2 x=8 x=2 and x=8 There are no true solutions to the equation.

To find the true solution(s) to the radical equation , we need to check the solutions obtained from squaring both sides of the equation.The solutions obtained are and . However, we need to verify if these solutions satisfy the original equation.Let's substitute into the original equation: This is not true, so is not a valid solution.Now, let's substitute into the original equation: This is true, so is a valid solution.Therefore, the true solution to the radical equation is .