Question
21. Write the noble gas abbreviated e configuration for the following: ex.)[Ne]3s^2. __ In __ Ba __
Solution
4.2
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Resposta
To write the noble gas abbreviated electron configuration for barium (Ba), we need to follow these steps:1. Identify the nearest preceding noble gas to barium.2. Write the electron configuration for barium starting from the noble gas core.Barium (Ba) has an atomic number of 56. The nearest preceding noble gas is xenon (Xe), which has an atomic number of 54.The electron configuration for xenon is:
Now, we add the remaining electrons to reach barium's total of 56 electrons:- After xenon, we have 2 electrons in the 6s orbital.So, the noble gas abbreviated electron configuration for barium (Ba) is:
Therefore, the noble gas abbreviated electron configuration for barium (Ba) is: