Select the correct answer. Complete the square for the following quadratic equation to determine its solutions in location of its extreme value. y=-x^2+4x+12 A. x=-2,6 extreme value at (2,12) B. x=2pm 2sqrt (7) extreme value at (2,16) C. x=2pm 2sqrt (7) extreme value at (2,12) D. x=-2,6 extreme value at (2,16) c ) A B

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Answer 1

To complete the square for the quadratic equation

, we can rewrite it in the form

, where

represents the location of the extreme value.Step 1: Factor out the coefficient of

from the first two terms:

Step 2: Add and subtract the square of half the coefficient of

inside the parentheses:

So, the quadratic equation in completed square form is

.The extreme value occurs at the vertex of the parabola, which is at

.Therefore, the correct answer is D.

extreme value at

.

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