Identify an equation in slope-intercept form for the line parallel to y=5x+2 that passes through (-6,-1) A. y=-5x-11 B y=5x-29 C y=(1)/(5)x+(1)/(6) D y=5x+29

## Step 1: Identify the slope of the given lineThe given line is in slope-intercept form, which is , where is the slope and is the y-intercept. In this case, the slope of the given line is 5.## Step 2: Use the point-slope form to find the equation of the parallel lineSince the parallel line has the same slope as the given line, its slope is also 5. We can use the point-slope form of a line, which is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line. Substituting the given point \((-6, -1)\) and the slope 5, we get: ## Step 3: Simplify the equation to slope-intercept formTo simplify the equation to slope-intercept form, we need to distribute the 5 on the right side of the equation and then subtract 1 from both sides: