Determine which equation has the same solutions as the equation below. 4x^2+32x-28=0 A. (x+8)^2=57 B. 4(x+4)^2=36 C. 4(x+8)^2=28 D. (x+4)^2=23 D C ) A B

To determine which equation has the same solutions as the given equation , we need to find the equation that can be transformed into the standard form of a quadratic equation, which is . Let's analyze each option:A. Expanding this equation, we get , which simplifies to . This equation does not match the given equation.B. 4(x^2 + 8x + 16) = 36 4x^2 + 32x + 64 = 36 4x^2 + 32x + 28 = 0 4(x+8)^{2}=28 4(x^2 + 16x + 64) = 28 4x^2 + 64x + 256 = 28 4x^2 + 64x + 228 = 0 (x+4)^{2}=23 x^2 + 8x + 16 = 23 x^2 + 8x - 7 = 0 4(x+4)^{2}=36$.