Pergunta

Solve using substitution. 2x+6y=8 3x+7y=4 square square
Solução

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IkerVeterano · Tutor por 10 anos
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To solve the system of equations using substitution, we can solve one equation for one variable and then substitute that expression into the other equation.
Let's solve the first equation for x:
2x + 6y = 8
2x = 8 - 6y
x = 4 - 3y
Now we can substitute this expression for x into the second equation:
3x + 7y = 4
3(4 - 3y) + 7y = 4
12 - 9y + 7y = 4
12 - 2y = 4
-2y = -8
y = 4
Now that we have the value of y, we can substitute it back into the expression for x:
x = 4 - 3y
x = 4 - 3(4)
x = 4 - 12
x = -8
Therefore, the solution to the system of equations is x = -8
Let's solve the first equation for x:
2x + 6y = 8
2x = 8 - 6y
x = 4 - 3y
Now we can substitute this expression for x into the second equation:
3x + 7y = 4
3(4 - 3y) + 7y = 4
12 - 9y + 7y = 4
12 - 2y = 4
-2y = -8
y = 4
Now that we have the value of y, we can substitute it back into the expression for x:
x = 4 - 3y
x = 4 - 3(4)
x = 4 - 12
x = -8
Therefore, the solution to the system of equations is x = -8
and y = 4
.
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