The zeroes of f(x)=x^3+3x^2+2x are 0,1,2 1,2 -2,-1,0 -1,-2 1,3,2

Question

Answer 1

To find the zeroes of the polynomial function

, we need to solve the equation

.We can start by factoring the polynomial. Notice that

is a common factor in each term:

Now, we can set each factor equal to zero and solve for

:

To solve the quadratic equation

, we can use the quadratic formula:

In this case,

,

, and

. Plugging these values into the quadratic formula, we get:

\frac{-3 \pm \sqrt{9 - 8}}{2}

x = \frac{-3 \pm \sqrt{1}}{2}

x = \frac{-3 \pm 1}{2}

x = \frac{-3 + 1}{2} = -1

x = \frac{-3 - 1}{2} = -2

f(x) = x^3 + 3x^2 + 2x

0

-1

-2$.

Question