Exercise 1. Une graphical method to solve the following. it. x^2-1=0 11 x^2+2x+1=0 x^2+3x-4=0 d x^2-4x+6=0 The quadratic function I'interseets the x-axis at the points (1,0) and (-4,0) What is the solution Net of the equation f(x)=0 At what values of does the graph of the equation y=(x+2)(x-6) Naxis?

To solve the given quadratic equations using the graphical method, we need to find the points where the graph of the quadratic function intersects the x-axis. These points represent the solutions to the equation.a) To find the solutions, we set the equation equal to zero and solve for x: So, the solutions to the equation are and .b) To find the solutions, we set the equation equal to zero and solve for x: So, the solution to the equation is .c) To find the solutions, we set the equation equal to zero and solve for x: or or So, the solutions to the equation are and .d) To find the solutions, we set the equation equal to zero and solve for x: This quadratic equation does not have real solutions as the discriminant is negative.So, the equation has no real solutions.The quadratic function intersects the x-axis at the points and . Therefore, the solutions to the equation are and .At what values of x does the graph of the equation intersect the x-axis?To find the values of x where the graph intersects the x-axis, we set the equation equal to zero and solve for x: or or So, the graph of the equation intersects the x-axis at the points and .