Solve each equation. (x+4)^2=3x+40

To solve the equation (x+4)^{2} = x^2 + 8x + 16 x^2 + 8x + 16 = 3x + 40 x^2 + 8x + 16 - 3x - 40 = 0 x^2 + 5x - 24 = 0 (x + 8)(x - 3) = 0 x + 8 = 0 x - 3 = 0 x x = -8 x = 3 (x+4)^{2}=3x+40 x = -8 x = 3$.