Página inicial
/
Matemática
/
muitipiy hhe following intergers. " 1.) "(4)(11)= 27(-5)(-9)= 3.7(10)(-10)= 4.7(-9)(-8)= 57(20)(-4)= 6.7(-12)(-5)= 7.)(30)(-3)=

Question

MUITIPIY HHE fOllowing intergers. " 1.) "(4)(11)= 27(-5)(-9)= 3.7(10)(-10)= 4.7(-9)(-8)= 57(20)(-4)= 6.7(-12)(-5)= 7.)(30)(-3)= 8.7(4)(7)= 9.)(15)(-2)= 10.7(25)(3)=

Solution

Verificación de expertos
4.6 (312 Votos)
Inês Mestre · Tutor por 5 anos

Resposta

1. 442. 12153. -1004. 725. -806. 607. -908. 28a. -2b. 802.5

Explicação

1. Multiplying two positive integers results in a positive product. .2. Multiplying three integers, where two of them are negative, results in a positive product. \(27 \times (-5) \times (-9) = 1215\).3. Multiplying two integers, one positive and one negative, results in a negative product. \(10 \times (-10) = -100\).4. Multiplying two negative integers results in a positive product. \((-9) \times (-8) = 72\).5. Multiplying two integers, one positive and one negative, results in a negative product. \(20 \times (-4) = -80\).6. Multiplying two negative integers results in a positive product. \((-12) \times (-5) = 60\).7. Multiplying two integers, one positive and one negative, results in a negative product. \(30 \times (-3) = -90\).8. Multiplying two positive integers results in a positive product. .a. Multiplying two integers, one positive and one negative, results in a negative product. \(1 \times (-2) = -2\).b. Multiplying three positive numbers results in a positive product. .