instructions Consider the function f(x)=x^2+bx-16 where b is a constant. Activity 1 of 2 If the function has an axis of symmetry at x=5 what is the value of b? b=-10 Activity 2 of 2 If b=-6 what are the zero(s ) of the function? x_(1)=? Choose. and x_(2)= square v Choose -1 -6 -8 -2

Question

Answer 1

To find the value of

when the axis of symmetry is at

, we can use the formula for the axis of symmetry of a quadratic function, which is given by:

For the given function \( f(x) = x^2 + bx - 16 \), the coefficient

is 1. Plugging in the given axis of symmetry:

Solving for

:

So, the value of

is

.Now, let's find the zeros of the function when

. The function becomes:

To find the zeros, we solve the equation:

We can use the quadratic formula:

For our equation,

,

, and

. Plugging these values into the quadratic formula:

This gives us two solutions:

So, the zeros of the function are

and

.Therefore, the correct choices are:

Question