Página inicial
/
Matemática
/
6) calcule: a) lim _(xarrow -1)sqrt [3]((2x^3-11x-1)/(-3x^3)-5x-1) b) lim _(xarrow 2)(x^3-2x^2+3x-2) c) lim _(xarrow

Question

6) Calcule: a) lim _(xarrow -1)sqrt [3]((2x^3-11x-1)/(-3x^3)-5x-1) b) lim _(xarrow 2)(x^3-2x^2+3x-2) c) lim _(xarrow -1)(x^2-3x+5)/(x+3)

Solution

Verificación de expertos
4.6 (275 Votos)
Edilson Mestre · Tutor por 5 anos

Resposta

Vamos corrigir e resolver cada uma das limitações:a) Para resolver essa limitação, primeiro substituímos na expressão dentro da raiz cúbica: A a raiz cúbica dessa fração:\[\sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{8}{7}} = \sqrt[3]{\frac{