Determine the empirical formulas for the compound with the following percent composition: 36.2% aluminum and 63.8% 3.8% sulfur Al_(2)S_(4) Al_(2)S_(3) Al_(3)S_(2) AlS_(3) Multiple Choice 1 point

To determine the empirical formula for the compound with the given percent composition, we need to convert the percentages to grams and then to moles.Given:- Aluminum (Al): 36.2%- Sulfur (S): 63.8%Assume we have 100 grams of the compound. This means we have:- 36.2 grams of Al- 63.8 grams of SNext, we convert the masses to moles using the molar masses of aluminum (Al) and sulfur (S):- Molar mass of Al = 26.98 g/mol- Molar mass of S = 32.06 g/molCalculate the moles of each element: Next, we find the simplest whole number ratio of the moles of Al to S: To get whole numbers, we can multiply both ratios by a common factor to get the smallest whole number ratio. In this case, multiplying by 2 gives: Thus, the empirical formula for the compound is: So, the correct answer is: