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4) the equation of line p is y+5=-10(x+2) line q is perpendicular to line p and passes through (-1,-1) what is the equation of line q?

Question

4) The equation of line p is y+5=-10(x+2) Line q is perpendicular to line p and passes through (-1,-1) What is the equation of line q?

Solution

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Resposta

To find the equation of line q, we first need to determine the slope of line p. The equation of line p is given as . We can rewrite this in slope-intercept form (y = mx + b) to find the slope. The slope of line p is -10. Since line q is perpendicular to line p, the slope of line q is the negative reciprocal of the slope of line p. Therefore, the slope of line q is .Now, we use the point-slope form of the equation of a line, which is , where m is the slope and is a point on the line. We are given that line q passes through the point . Therefore, the equation of line q is .