What is the solution set to the equation 0=(3a+1)^2(a-4) A) (1)/(3),-4 B) -(1)/(3),4 C) -(1)/(3),(1)/(3),-4 D) -(1)/(3),(1)/(3),4

To find the solution set to the equation , we need to find the values of that make the equation equal to zero.The equation is a product of two factors: and . For the equation to be equal to zero, at least one of the factors must be equal to zero.Let's consider the first factor, . This factor is a perfect square, so it is always non-negative. The only way for it to be equal to zero is if . Solving this equation, we get .Now let's consider the second factor, . This factor is a linear term, so it can be equal to zero if .Therefore, the solution set to the equation is .So, the correct answer is B) .