Question
For Question 1: a) Complete the table b) Plot the points and sketch the graph c) Label on the graph any x -intercepts, y -intercepts and vertices. You will earn: - 2 pts for correctly completing the table ( 1 pt for partially correct table) - 2 pts for plotting your points correctly and sketching a graph through them - 2 pts for labeling the key points on the graph (intercepts and vertices) 1. Given f(x)=2 x^2+8 x+4 a) Complete the table x & f(x) -4 & -3 & -2 & -1 & 0 & b) Plot the points and sketch the graph
Solution
4.5
(248 Votos)
Renato
Avançado · Tutor por 1 anos
Resposta
To complete the table and sketch the graph for the function \( f(x) = 2x^2 + 8x + 4 \), we need to evaluate the function at each given
-value.### a) Complete the Table1. **For
:**
2. **For
:**
3. **For
:**
4. **For
:**
5. **For
:**
The completed table is:
### b) Plot the Points and Sketch the GraphPlot the points \((-4, 4)\), \((-3, -2)\), \((-2, -4)\), \((-1, -2)\), and \((0, 4)\) on a coordinate plane. Connect these points with a smooth curve to form a parabola.### c) Label Key Points on the Graph- **Vertex:** The vertex of a parabola in the form
can be found using the formula
. For this function:
Substituting
back into the function gives \( f(-2) = -4 \). So, the vertex is \((-2, -4)\).- **
-Intercepts:** Set \( f(x) = 0 \) and solve for
:
Divide the entire equation by 2:
Use the quadratic formula
:
The
-intercepts are \((-2 + \sqrt{2}, 0)\) and \((-2 - \sqrt{2}, 0)\).- **
-Intercept:** This occurs when
, so the
-intercept is \((0, 4)\).Label these points on your graph accordingly.