Differentiate y=2x(3-x) (dy)/(dx)=3x-2x^2 (dy)/(dx)=6-2x (dy)/(dx)=6-4x (dy)/(dx)=6x-4x^2

To differentiate the function \( y = 2x(3 - x) \), we can use the product rule. The product rule states that if you have a function \( y = u(x)v(x) \), then the derivative is given by: Here, let \( u(x) = 2x \) and \( v(x) = 3 - x \).First, we find the derivatives of \( u(x) \) and \( v(x) \): Now, apply the product rule: So, the correct answer is: