The maximum height H of an object launched with Initial velocity v_(0) at an angle Theta is given by the following formula. H=(v_(0)^2sin^2Theta )/(2g) If g=9.8m/s^2 find the height of an object when v_(0)=80m/s and Theta =(3pi )/(5) rad. Do not round any Intermediate computations. Round your answer to the nearest hundredth. H=square m

To find the height of the object, we can use the formula given: Given: rad Substituting the values into the formula, we get: Calculating the value of : Now, substituting this value back into the formula: Simplifying further: $H=\frac