4. Find the empirical formula for a compound with 65.4% C. 5.5% H, and 29.1% a a. C_(5)H_(5)O_(1) b. C_(3)H_(3)O C. C_(5)H_(6)O_(2) d. CHO

To find the empirical formula for the compound, we need to determine the simplest whole number ratio of the elements present in the compound.Given information:- 65.4% Carbon (C)- 5.5% Hydrogen (H)- 29.1% Oxygen (O)Step 1: Convert the percentages to grams.- Carbon (C): 65.4 g- Hydrogen (H): 5.5 g- Oxygen (O): 29.1 gStep 2: Convert the grams to moles.- Carbon (C): 65.4 g / 12.01 g/mol = 5.45 mol- Hydrogen (H): 5.5 g / 1.008 g/mol = 5.47 mol- Oxygen (O): 29.1 g / 16.00 g/mol = 1.81 molStep 3: Determine the simplest whole number ratio of the elements.- Divide each mole value by the smallest mole value (1.81 mol).- Carbon (C): 5.45 mol / 1.81 mol = 3- Hydrogen (H): 5.47 mol / 1.81 mol = 3- Oxygen (O): 1.81 mol / 1.81 mol = 1The empirical formula for the compound is .Therefore, the correct answer is:b.