In a certain Algebra 2 class of 30 students,11 of them play basketball and 9 of them play baseball. There are 15 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball? Answer square

To find the probability that a student chosen randomly from the class plays both basketball and baseball, we need to determine the number of students who play both sports.

Let's denote the number of students who play both basketball and baseball as x.

We know that there are 11 students who play basketball and 9 students who play Since there are 15 students who play neither sport, the total number of students who play either basketball or baseball or both is 30 - 15 = 15.

Using the principle of inclusion-exclusion, we can write the equation:

11 + 9 - x = 15

Solving for x, we get:

x = 11 + 9 - 15
x = 5

So, there are 5 students who play both basketball and baseball.

The probability that a student chosen randomly from the class plays both basketball and baseball is the number of students who play both sports divided by the total number of students in the class:

Probability = (Number of students who play both sports) / (Total number of students in the class)
Probability = 5 / 30
Probability = 1/6

Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is 1/6.