Identify an equation in point-slope form for the line perpendicular to y=-2x+8 that passes through (-3,9) A. y-9=(1)/(2)(x+3) B. y+3=(1)/(2)(x-9) C. y+9=2(x-3)fv D. y-9=-2(x+3)

To find the equation of a line perpendicular to that passes through , we need to determine the slope of the perpendicular line.The slope of the given line is . The slope of a line perpendicular to this line is the negative reciprocal of , which is .Now, we can use the point-slope form of a line equation, which is , where is a point on the line and is the slope.Substituting the values, we have: Simplifying the equation, we get: Therefore, the equation in point-slope form for the line perpendicular to that passes through is:A.