10. Find an equation of the line passing through the point (-2,2) that is perpendicular to the line y=-(4)/(3)x-6 square Do not use decimal approximations in your answer. Practice similar Help me with this

1. The slope of the given line is .2. The slope of a line perpendicular to this line would be the negative reciprocal of , which is .3. Using the point-slope form of a line, \(y - y_1 = m(x - x_1)\), where is the slope and \((x_1, y_1)\) is a point on the line, we can plug in the given point (-2,2) and the slope .4. This gives: \(y - 2 = 3(x + 2)\).5. Simplifying, we get the equation of the line as .