Question
which value (s) of m will (x+m)^2-2(x+m)-11=x-1 have Two different negative roots?
Solution
4.5
(230 Votos)
Alexandre
Profissional · Tutor por 6 anos
Resposta
To find the value of
such that the equation \((x+n)^2 - 2(x+n) - 11 = x - 1\) has two different negative roots, we first need to simplify and rearrange the equation.Start by expanding the left side:
Simplify this expression:
Set it equal to the right side of the original equation:
Rearrange all terms to one side:
This is a quadratic equation in the form
, where
,
, and
.For the quadratic equation to have two different negative roots, the following conditions must be satisfied:1. The discriminant must be positive:
.2. Both roots must be negative.First, calculate the discriminant:
Simplify:
Set the discriminant greater than zero:
Solve for
:
-
Check these conditions:1.
\[ 2n > 3 \quad \Rightarrow \quad n > \frac{3}{2} \]2.
Solve
using the quadratic formula or factorization: The roots of
are found using the quadratic formula:
The critical points are
and
. Since
, we have approximately
and
. The inequality
holds for
.Combine all conditions:-
The only interval satisfying all conditions is
.Thus, the integer value of
that satisfies all conditions is
.