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which value (s) of m will (x+m)^2-2(x+m)-11=x-1 have two different negative roots?

Question

which value (s) of m will (x+m)^2-2(x+m)-11=x-1 have Two different negative roots?

Solution

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4.5 (230 Votos)
Alexandre Profissional · Tutor por 6 anos

Resposta

To find the value of such that the equation \((x+n)^2 - 2(x+n) - 11 = x - 1\) has two different negative roots, we first need to simplify and rearrange the equation.Start by expanding the left side: Simplify this expression: Set it equal to the right side of the original equation: Rearrange all terms to one side: This is a quadratic equation in the form , where , , and .For the quadratic equation to have two different negative roots, the following conditions must be satisfied:1. The discriminant must be positive: .2. Both roots must be negative.First, calculate the discriminant: Simplify: Set the discriminant greater than zero: Solve for : - Check these conditions:1. \[ 2n > 3 \quad \Rightarrow \quad n > \frac{3}{2} \]2. Solve using the quadratic formula or factorization: The roots of are found using the quadratic formula: The critical points are and . Since , we have approximately and . The inequality holds for .Combine all conditions:- The only interval satisfying all conditions is .Thus, the integer value of that satisfies all conditions is .