Certa loja decidiu fazer uma pesquisa para saber a altura média de seus funcionários. Os dados estão presentes na tabela a seguir: multicolumn(2)(c)( Altura ) & Frequência 1,53 mid-1,59 & 5 & 1,59 mid-1,65 & 4 & 1,65 mid-1,71 & 12 & 1,71 mid-1,77 & 8 & 1,77 mid-1,83 & 9 & Com base nas informações presentes na tabela, analise os itens que seguem: I- A amplitude total é igual a 0,36. II - O comprimento do intervalo das classes é 0,05. III - A frequência relativa da segunda classe é igual a 496. IV - A classe de maior frequência é a 3^ (n ) classe. A. Apenas o item I está correto. B. Apenas os itens I e III estão corretos. c. Apenas o item II está correto. D. Apenas o item IV está correto.

## Step 1: Calculate the Total Range (Amplitude Total)### The total range is calculated by subtracting the smallest lower bound from the largest upper bound in the class intervals. Here, the smallest lower bound is and the largest upper bound is . Therefore, the total range is .## Step 2: Determine the Length of Class Intervals### The length of each class interval is determined by subtracting the lower bound from the upper bound of any class. For example, for the first class , the length is .## Step 3: Calculate the Relative Frequency of the Second Class### The relative frequency is calculated by dividing the frequency of the class by the total number of observations. The second class has a frequency of 4. The total frequency is . Thus, the relative frequency of the second class is or .## Step 4: Identify the Class with the Highest Frequency### The class with the highest frequency is identified by comparing the frequencies of all classes. The third class has the highest frequency of 12.