) 6x+2y=12 2x+2y=8 4x+12y=2 4

To solve the system of equations, we can use the method of substitution or elimination. Let's use the elimination method.First, we can eliminate the variable y by multiplying the second equation by -2 and adding it to the first equation:-2(2x + 2y) + (6x + 2y) = -2(8) + 12-4x - 4y + 6x + 2y = -16 + 122x - 2y = -4Now, we can eliminate the variable y by multiplying the third equation by -1/12 and adding it to the first equation:-1/12(4x + 12y) + (6x + 2y) = -1/12(2) + 12-1/3x - y + 6x + 2y = -1/6 + 125/3x + y = 12 - 1/65/3x + y = 71/6Now we have two new equations:2x - 2y = -45/3x + y = 71/6We can solve this system of equations by multiplying the second equation by 2 and adding it to the first equation:2(5/3x + y) + (2x - 2y) = 2(71/6) + (-4)10/3x + 2y + 2x - 2y = 71/3 - 414/3x = 65/3x = 65/14Now we can substitute the value of x into the second equation to find the value of y:5/3(65/14) + y = 71/6y = 71/6 - 5/3(65/14)y = 71/6 - 25/6y = 46/6y = 23/3Therefore, the solution to the system of equations is x = 65/14 and y = 23/3.