Question
Problem 3: 3CaCO_(3)+2FePO_(4)arrow Ca_(3)(PO_(4))_(2)+Fe_(2)(CO_(3))_(3) Given: 50 grams of 1 poin calcium carbonate and 15 grams of Iron (III)phosphate. Find: Which of the reagents is the limiting reagent? calcium carbonate iron III phosphate calcium phosphate iron III carbonate
Solution
4
(235 Votos)
Suelen
Mestre · Tutor por 5 anos
Resposta
To determine the limiting reagent, we need to calculate the number of moles of each reactant and compare them to the stoichiometry of the balanced chemical equation.Given:- 50 grams of calcium carbonate (CaCO3)- 15 grams of iron(III) phosphate (FePO4)First, let's calculate the molar masses of the reactants:- Molar mass of CaCO3 = 40.08 (Ca) + 12.01 (C) + 3 × 16.00 (O) = 100.09 g/mol- Molar mass of FePO4 = 55.85 (Fe) + 4 × 15.999 (O) + 30.97 (P) = 150.82 g/molNow, let's calculate the number of moles of each reactant:- Moles of CaCO3 = 50 g / 100.09 g/mol = 0.5 mol- Moles of FePO4 = 15 g / 150.82 g/mol = 0.1 molNext, we need to compare the mole ratio of the reactants to the stoichiometry of the balanced chemical equation:- The balanced chemical equation is: 3CaCO3 + 2FePO4 → Ca3(PO4)2 + Fe2(CO3)3- According to the equation, 3 moles of CaCO3 react with 2 moles of FePO4.Now, let's calculate the ratio of the moles of each reactant to the stoichiometry of the balanced chemical equation:- Ratio of CaCO3 = 0.5 mol / 3 = 0.167- Ratio of FePO4 = 0.1 mol / 2 = 0.05Since the ratio of FePO4 is smaller than the ratio of CaCO3, iron(III) phosphate (FePO4) is the limiting reagent.Therefore, the correct answer is: iron(III) phosphate.