) 2times 1+x_(2)=1 ytimes (+5x_(2)+3x_(2)+x_(4)=y 3times 1-14x_(2)+3x_(3)+5xy=1 6x_(4)+4times 2+3y_(2)=30

Question

Answer 1

The given system of equations is:

Let's solve this system step by step.1. Simplify the first equation:

2. Simplify the second equation:

3. Simplify the third equation:

4. Simplify the fourth equation:

Now we have the following system of equations:

We can solve this system by substitution or elimination method. Let's use the substitution method.From the first equation, we have

. Substitute this value into the other equations:

Simplifying the first equation, we get

.Substituting

and

into the second equation, we have:

Substituting

and

into the third equation, we have:

Now we have the following system of equations:

We can solve this system by substitution or elimination method. Let's use the substitution method.From the first equation, we have

. Substitute this value into the other equations:

We cannot solve this system further without additional information. Therefore, the solution to the given system of equations is:

Question