Question
Question 10 (Multiple (07.02 LC) Factor completely 3ab(x+1)-2(x+1) Prime (x+1)(3ab+2) (x+1)(3ab-2) (x+1)(ab)
Solution
4.2
(350 Votos)
Giovanni
Avançado · Tutor por 1 anos
Resposta
The factored form of the given expression is \((x+1)(3ab-2)\).
Explicação
## Step 1The given expression is \(3ab(x+1)-2(x+1)\). We can see that both terms have a common factor of \((x+1)\).## Step 2We can factor out the common factor \((x+1)\) from both terms. This is done by dividing each term by the common factor.### \(3ab(x+1)-2(x+1) = (x+1)(3ab-2)\)