Multiple Choice 1 point Determine the empirical formula:for the compounds with the following percent composition: 80.38% bismuth, 18.46% oxygen, and d 1.16% hydrogen 1.16% BiO_(3)H_(2) BiO_(3)H_(3) BiO_(2)H_(3) Bi_(2)O_(3)H_(3)

Question

Multiple Choice 1 point Determine the empirical formula:for the compounds with the following percent composition: 80.38% bismuth, 18.46% oxygen, and d 1.16% hydrogen 1.16% BiO_(3)H_(2) BiO_(3)H_(3) BiO_(2)H_(3) Bi_(2)O_(3)H_(3)

Answer 1

To determine the empirical formula, we need to convert the given percentages to moles and then find the simplest whole number ratio.Given:- Bismuth (Bi): 80.38%- Oxygen (O): 18.46%- Hydrogen (H): 1.16%Step 1: Convert the percentages to grams.- Bi: 80.38 g- O: 18.46 g- H: 1.16 gStep 2: Convert the grams to moles using the molar masses of each element.- Bi: 80.38 g / 208.98 g/mol = 0.386 mol- O: 18.46 g / 16.00 g/mol = 1.148 mol- H: 1.16 g / 1.01 g/mol = 1.146 molStep 3: Find the simplest whole number ratio by dividing each mole value by the smallest mole value.- Bi: 0.386 mol / 0.386 mol = 1- O: 1.148 mol / 0.386 mol = 2.97 ≈ 3- H: 1.146 mol / 0.386 mol = 2.97 ≈ 3Therefore, the empirical formula for the compound is BiO3H3.Answer: BiO3H3

Question

Multiple Choice 1 point Determine the empirical formula:for the compounds with the following percent composition: 80.38% bismuth, 18.46% oxygen, and d 1.16% hydrogen 1.16% BiO_(3)H_(2) BiO_(3)H_(3) BiO_(2)H_(3) Bi_(2)O_(3)H_(3)

Solution

Resposta