The length of a rectangular poster is 9 more inches than three times its width. The area of the poster is 264 square inches . Solve for the dimensions (length and width) of the poster.

Question

Answer 1

Let's denote the width of the rectangular poster as

inches. According to the problem, the length poster is 9 inches more than three times its width. Therefore, the length can be expressed as

inches.The area of the rectangle is given by the product of its length and width, which is 264 square inches. So, we can set up the equation:

Expanding the equation, we get:

To solve this quadratic equation, we can rearrange it to standard form:

Now, we can solve this quadratic equation using the quadratic formula:

In this case,

,

, and

. Plugging these values into the quadratic formula, we get:

Now, we have two possible solutions for

:

Since the width cannot be negative, we discard

and take

inches as the width of the poster.Now, we can find the length of the poster using the expression

:

Therefore, the dimensions of the rectangular poster are 8 inches in width and 33.

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