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(1)) the equation of line p is y+7=-(1)/(2)(x-5) line q is parallel to line p and passes through (4,8) what is the equation of line q?

Question

(1)) The equation of line p is y+7=-(1)/(2)(x-5) Line q is parallel to line p and passes through (4,8) What is the equation of line q?

Solution

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4.2 (386 Votos)
Maria Helena Mestre · Tutor por 5 anos

Resposta

To find the equation of line q, we need to use the point-slope form of a linear equation, which is given by: where is a point on the line and is the slope of the line.Since line q is parallel to line p, it will have the same slope as line p. The slope of line p can be found by rearranging the equation of line p in slope-intercept form (i.e., ), where is the slope and is the y-intercept.Rearranging the equation of line p, we have: Simplifying further, we get: From this equation, we can see that the slope of line p is .Now, we can use the point-slope form to find the equation of line q. We know that line q passes through the point , so we can substitute these values into the point-slope form: Simplifying further, we get: Therefore, the equation of line q is .