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40 line u has an equation of y+6=(3)/(2)(x-6) line v is perpendicular to line u and passes through (2,-1) what is the equation of line

Question

40 Line u has an equation of y+6=(3)/(2)(x-6) Line v is perpendicular to line u and passes through (2,-1) What is the equation of line v? (1) Write the equation in slope-intercept form Write the numbers in the equation as simplified proper fractions,improper fractions, or integers. square

Solution

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Inês Maria Especialista · Tutor por 3 anos

Resposta

To find the equation of line v, we first need to find the slope of line u. We can do this by rearranging the equation of line u into slope-intercept form (y = mx + b), where m is the slope.Given: Step 1: Distribute the on the right side of the equation: Step 2: Subtract 6 from both sides to isolate y: Now we have the equation of line u in slope-intercept form: . The slope of line u is .Since line v is perpendicular to line u, the slope of line v will be the negative reciprocal of the slope of line u. Therefore, the slope of line v is .Step 3: Use the point-slope form of a linear equation to find the equation of line v. The point-slope form is given by: , where is a point on the line and m is the slope.Given point: Slope: Substitute these values into the point-slope form: Simplify: Step 4: Rearrange the equation into slope-intercept form: Combine like terms: Therefore, the equation of line v in slope-intercept form is: