Given the quadratic equation y=5x^2+8x+9 solve for the y-coordinate of the parabola when x=-3. 32 24 30 25

To solve for the y-coordinate of the parabola when $x=-3$, we substitute $x=-3$ into the equation $y=5x^{2}+8x+9$.<br /><br />$y = 5(-3)^{2} + 8(-3) + 9$<br /><br />$y = 5(9) - 24 + 9$<br /><br />$y = 45 - 24 + 9$<br /><br />$y = 30$<br /><br />Therefore, the y-coordinate of the parabola when $x=-3$ is 30.