Pergunta

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y) y=x^2-6 Answer Attemptiout of 2 square
Solução

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SérgioVeterano · Tutor por 10 anos
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To find the coordinates of the vertex of the parabola given by the equation y = x^2 - 6
x = -\frac{b}{2a}
For the given equation y = x^2 - 6
x = -\frac{0}{2 \cdot 1} = 0
Now that we have the of the vertex, we can find the y-coordinate by substituting x = 0
y = (0)^2 - 6 = -6
Therefore, the coordinates of the vertex of the parabola y = x^2 - 6
, we can use the vertex formula for a parabola in the form y = ax^2 + bx + c
. The vertex formula is given by:
x = -\frac{b}{2a}
For the given equation y = x^2 - 6
, we have a = 1
, b = 0
, and c = -6
. Plugging these values into formula, we get:
x = -\frac{0}{2 \cdot 1} = 0
Now that we have the of the vertex, we can find the y-coordinate by substituting x = 0
back into the original equation:
y = (0)^2 - 6 = -6
Therefore, the coordinates of the vertex of the parabola y = x^2 - 6
are (0, -6)
.
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