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8) Find the x-and y-intercepts of the graph of the linear equation 3x=6y+2 a) ((2)/(3),0),(0,-3) b) (-3,0),(0,(2)/(3)) c) ((2)/(3),0),(0,(1)/(3)) d) ((2)/(3),0),(0,-(1)/(3)) A B C D

Pergunta

8) Find the x-and y-intercepts of the graph of
the linear equation 3x=6y+2
a) ((2)/(3),0),(0,-3)
b) (-3,0),(0,(2)/(3))
c) ((2)/(3),0),(0,(1)/(3))
d) ((2)/(3),0),(0,-(1)/(3))
A
B
C
D

8) Find the x-and y-intercepts of the graph of the linear equation 3x=6y+2 a) ((2)/(3),0),(0,-3) b) (-3,0),(0,(2)/(3)) c) ((2)/(3),0),(0,(1)/(3)) d) ((2)/(3),0),(0,-(1)/(3)) A B C D

Solução

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TatianiElite · Tutor por 8 anos

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To find the x-intercept, we set y = 0 and solve for x:<br /><br />$3x = 6(0) + 2$<br /><br />$3x = 2$<br /><br />$x = \frac{2}{3}$<br /><br />So the x-intercept is $(\frac{2}{3}, 0)$.<br /><br />To find the y-intercept, we set x = 0 and solve for y:<br /><br />$3(0) = 6y + 2$<br /><br />$0 = 6y + 2$<br /><br />$6y = -2$<br /><br />$y = -\frac{1}{3}$<br /><br />So the y-intercept is $(0, -\frac{1}{3})$.<br /><br />Therefore, the correct answer is D) $(\frac{2}{3}, 0), (0, -\frac{1}{3})$.
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