1+(1)/(2)+(1)/(4)+(1)/(8)

To solve the expression $1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8}$, we need to add these fractions together.

First, let's convert all terms to have a common denominator. The least common denominator for 2, 4, and 8 is 8.

1. Convert $1$ to a fraction with a denominator of 8:
$$1 = \frac{8}{8}$$

2. Convert $\frac{1}{2}$ to a fraction with a denominator of 8:
$$\frac{1}{2} = \frac{4}{8}$$

3. $\frac{1}{4}$ already has a denominator of 4, which is a factor of 8:
$$\frac{1}{4} = \frac{2}{8}$$

4. $\frac{1}{8}$ already has a denominator of 8:
$$\frac{1}{8} = \frac{1}{8}$$

Now, add these fractions together:
$$\frac{8}{8} + \frac{4}{8} + \frac{2}{8} + \frac{1}{8} = \frac{8 + 4 + 2 + 1}{8} = \frac{15}{8}$$

So, the sum of $1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{8}$ is:
$$\frac{15}{8}$$

In decimal form, this is:
$$\frac{15}{8} = 1.875$$

Therefore, the correct answer is:
$$\boxed{\frac{15}{8}}$$