Pergunta

2 Calcule o resultado das expressões aplicando seus cor a) (5cdot 3-2^4)^1001=square b) 1500^(3^(2-2^3))-1889^(5^(2-4^2-3^2))=square c) (125cdot (5^3)^2)/((5^2))^(4)=square d) (2^14:2048)/(4.8)=square
Solução

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GertrudesProfissional · Tutor por 6 anos
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a) (5\cdot 3-2^{4})^{1001} = (15-16)^{1001} = (-1)^{1001} = -1
b) 1500^{(3^{2}-2^{3})}-1889^{(5^{2}-4^{2}-3^{2})} = 1500^{7}-1889^{6} = 1500^{7}-1889^{6}
c) \frac {125\cdot (5^{3})^{2}}{(5^{2})^{4}} = \frac {125\cdot 5^{6}}{5^{8}} = \frac {125}{5^{2}} = \frac {125}{25} = 5
d) \frac {2^{14}:2048}{4.8} = \frac {2^{14}}{2^{11}} \cdot \frac {1}{4.8} = 2^{3} \cdot \frac {1}{4.8} = 8 \cdot \frac {1}{4.8} = \frac {8}{4.8} = \frac {5}{3}
b) 1500^{(3^{2}-2^{3})}-1889^{(5^{2}-4^{2}-3^{2})} = 1500^{7}-1889^{6} = 1500^{7}-1889^{6}
c) \frac {125\cdot (5^{3})^{2}}{(5^{2})^{4}} = \frac {125\cdot 5^{6}}{5^{8}} = \frac {125}{5^{2}} = \frac {125}{25} = 5
d) \frac {2^{14}:2048}{4.8} = \frac {2^{14}}{2^{11}} \cdot \frac {1}{4.8} = 2^{3} \cdot \frac {1}{4.8} = 8 \cdot \frac {1}{4.8} = \frac {8}{4.8} = \frac {5}{3}
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