If h(z)=(4z-2)/(z-A) and h(3)=-2 what is the value of A? A=square (Simplify your answer.)

To find the value of $A$, we need to substitute $z = 3$ into the function $h(z)$ and set it equal to -2.

Given:
$$h(z) = \frac{4z - 2}{z - A}$$
and
$$h(3) = -2$$

Substitute $z = 3$ into the function:
$$h(3) = \frac{4(3) - 2}{3 - A} = -2$$

Simplify the numerator:
$$\frac{12 - 2}{3 - A} = -2$$
$$\frac{10}{3 - A} = -2$$

Now, solve for $A$:
$$10 = -2(3 - A)$$
$$10 = -6 + 2A$$
$$10 + 6 = 2A$$
$$16 = 2A$$
$$A = 8$$

Therefore, the value of $A$ is:
$$A = 8$$