R3. For the linear function y+3=-(5)/(2)(x-4) a. Name the form of the equation. b. Write the coordinates of the point that appears in the equation. C. Plot the graph. d. Transform the equation to slope -intercept form. e.Transform the equation to Ax+By=C form, where A, B. and C are integers. a. y=-4

a. The form of the equation is point-slope form.<br /><br />b. The coordinates of the point that appear in the equation are (4, -3).<br /><br />c. To plot the graph, you can start by plotting the point (4, -3) and then use the slope -5/2 to find another point on the line.<br /><br />d. To transform the equation to slope-intercept form, you can solve for y:<br />$y+3=-\frac {5}{2}(x-4)$<br />$y=-\frac {5}{2}(x-4)-3$<br />$y=-\frac {5}{2}x+10-3$<br />$y=-\frac {5}{2}x+7$<br /><br />To transform the equation to $Ax+By=C$ form, you can multiply both sides of the equation by 2 to eliminate the fraction:<br />$2y=-5(x-4)-6$<br />$2y=-5x+20-6$<br />$2y=-5x+14$<br />$5x+2y=14$<br /><br />e. The equation in $Ax+By=C$ form is $5x+2y=14$.