Given vectors a=langle -3,2rangle and b=langle 4,6rangle find 2a-4b Write your answer in component form. 2a-4b= square square

To find $2a-4b$, we first need to multiply each vector by their respective scalars.<br /><br />For vector $a$, multiplying by 2 gives us $2a = \langle -6, 4 \rangle$.<br /><br />For vector $b$, multiplying by 4 gives us $4b = \langle 16, 24 \rangle$.<br /><br />Now, we subtract $4b$ from $2a$:<br /><br />$2a - 4b = \langle -6, 4 \rangle - \langle 16, 24 \rangle = \langle -6 - 16, 4 - 24 \rangle = \langle -22, -20 \rangle$<br /><br />Therefore, $2a - 4b = \langle -22, -20 \rangle$.