d) (2^2:(4)/(3)-(1)/(2))cdot (6)/(5)-17 e) 23(1)/(4)cdot (7)/(5)-13(1)/(4):(5)/(7) f) (1)/(2)+((-3)/(5))^2:(-1(4)/(5)) g) (4)/(-5)+(2)/(15):(-6)/(5) h) (1)/(5)cdot (-13)/(7)+(-8)/(7)cdot (1)/(5) Câu 5. Tính giá trị của các biểu thức sau: a) A=(2^6cdot 9^2)/(6^4)cdot 8 . b) B=(3^10cdot 2^10)/(16cdot 4^3)cdot 243 . c) C=(2^15cdot 9^4)/(6^6)cdot 8^(3) d) D=(2^4cdot 2^6)/(2^5)-(2^5cdot 15^3)/(6^3)cdot 10^(2) . i) E=(2^7cdot 9^3cdot 2022^0)/(3^5)cdot 8^(2) Câu 6. Tìm x , biết: a) (x)/(12)-(5)/(6)=(1)/(12) b) (2)/(3)-1(4)/(15)x=(-3)/(5) . c) 1(1)/(2)x-4=0,5 . d) -2^3+0,5x=1,5 Câu 7. Thực hiện các phép tính sau theo cách hợp lí nhất có thể: a) (1+(2)/(3)-(3)/(4))-(1+(5)/(4))+((2)/(5)-2) b) (5-(3)/(2)-(1)/(8)):(2-(5)/(2)-(3)/(4)) c) (2cdot 8^4cdot 27^2+4cdot 6^9)/(2^7)cdot 6^(7+2^7cdot 4cdot 9^3) Câu 8. Thực hiện phép tính: (5)/(7)cdot ((-3)/(11))+(5)/(7)cdot ((-8)/(11))+2(5)/(7) . b) (1+(2)/(3)-(1)/(4))cdot ((4)/(5)-(3)/(4))^2 (5^4cdot 20^4)/(25^5)cdot 4^(5) . d) (3(1)/(2)-0,5)cdot (1)/(27)+1(1)/(3)

Câu 5:<br />a) $A=\frac {2^{6}\cdot 9^{2}}{6^{4}\cdot 8} = \frac {64\cdot 81}{1296\cdot 8} = \frac {5184}{10368} = \frac {1}{3}$<br />b) $B=\frac {3^{10}\cdot 2^{10}}{16\cdot 4^{3}\cdot 243} = \frac {59049\cdot 1024}{16\cdot 64\cdot 243} = \frac {60466144}{196608} = 307.5$<br />c) $C=\frac {2^{15}\cdot 9^{4}}{6^{6}\cdot 8^{3}} = \frac {32768\cdot 6561}{46656\cdot 512} = \frac {2143588816}{238094656} = 8.999$<br />d) $D=\frac {2^{4}\cdot 2^{6}}{2^{5}}-\frac {2^{5}\cdot 15^{3}}{6^{3}\cdot 10^{2}} = \frac {2^{10}}{2^{5}}-\frac {2^{5}\cdot 3375}{216\cdot 100} = \frac {2^{5}}{1}-\frac {2^{5}\cdot 3375}{21600} = 32-\frac {675}{216} = 32-\frac {25}{8} = 31.625$<br />e) $E=\frac {2^{7}\cdot 9^{3}\cdot 2022^{0}}{3^{5}\cdot 8^{2}} = \frac {128\cdot 729\cdot 1}{243\cdot 64} = \frac {93312}{15552} = 6$<br /><br />Câu 6:<br />a) $\frac {x}{12}-\frac {5}{6}=\frac {1}{12}$ => $\frac {x}{12}=\frac {1}{12}+\frac {5}{6}$ => $\frac {x}{12}=\frac {1}{12}+\frac {10}{12}$ => $\frac {x}{12}=\frac {11}{12}$ => $x=11$<br />b) $\frac {2}{3}-1\frac {4}{15}x=\frac {-3}{5}$ => $\frac {2}{3}-\frac {19}{15}x=\frac {-3}{5}$ => $\frac {10}{15}-\frac {19}{15}x=\frac {-3}{5}$ => $\frac {10}{15}-\frac {19}{15}x=\frac {-9}{15}$ => $-\frac {9}{15}=\frac {19}{15}x$ => $x=-\frac {9}{19}$<br />c) $1\frac {1}{2}x-4=0,5$ => $\frac {3}{2}x-4=\frac {1}{2}$ => $\frac {3}{2}x=\frac {1}{2}+4$ => $\frac {3}{2}x=\frac {9}{2}$ => $x=3$<br />d) $-2^{3}+0,5x=1,5$ => $-8+0,5x=1,5$ => $0,5x=1,5+8$ => $0,5x=9,5$ => $x=19$<br /><br />Câu 7:<br />a) $(1+\frac {2}{3}-\frac {3}{4})-(1+\frac {5}{4})+(\frac {2}{5}-2)$<br />b) $(5-\frac {3}{2}-\frac {1}{8}):(2-\frac {5}{2}-\frac {3}{4})$<br />c) $\frac {2\cdot 8^{4}\cdot 27^{2}+4\cdot 6^{9}}{2^{7}\cdot 6^{7}+2^{7}\cdot 4\cdot 9^{3}}$<br /><br />Câu 8:<br />a) $\frac {5}{7}\cdot (\frac {-3}{11})+\frac {5}{7}\cdot (\frac {-8}{11})+2\frac {5}{7}$<br />b) $(1+\frac {2}{3}-\frac {1}{4})\cdot (\frac {4}{5}-\frac {3}{4})^{2}$<br />c) $\frac {5^{4}\cdot 20^{4}}{25^{5}\cdot 4^{5}}$<br />d) $(3\frac {1}{2}-0,5)\cdot \frac {1}{27}