A bicycle racer sprints near the end of a race to clinch a victory. The racer has an initial velocity of 10.95m/s and accelerates at the rate of 0.55m/s^2 for 6.75 s to accomplish this. hsb015@students, jefferson edu 0P65-F1-5F -4C-8974-54256 Part (a) What is his final velocity, in meters per second, after this period of acceleration? v_(f)=14.66 Correct! Part (b) The racer continues at this velocity to the finish line. If he was 330 m from the finish line when he started to accelerate, how much less time did it take him to finish than if he had not accelerated? Delta t=6.790 Correct! Part (c) One other racer was 5.5 m ahead when the winner started to accelerate, but was too tired to speed up and traveled at 12.5m/s until the finish line. If the winner continues to cycleat the same speed after crossing the finish line (to celebrate his victory)how far ahead of the loser will the winner be, in meters.when the loser finishes? Delta x=square

To solve part (c), we need to find the distance between the winner and the loser when the loser finishes the race.

Given information:
- The winner's final velocity after acceleration is $$v_f = 14.66 \, \text{m/s}$$ .
- The winner was 330 m from the finish line when he started to accelerate.
- The loser was 5.5 m ahead of the winner when the winner started to accelerate and traveled at a constant velocity of $$12.5 \, \text{m/s}$$ .

Step 1: Calculate the time it takes for the winner to finish the race.
Time taken by the winner to finish the race = $$\frac{330 \, \text{m}}{14.66 \, \text{m/s}} = 22.5 \, \text{s}$$

Step 2: Calculate the distance traveled by the loser during this time.
Distance traveled by the loser = $$12.5 \, \text{m/s} \times 22.5 \, \text{s} = 281.25 \, \text{m}$$

Step 3: Calculate the distance between the winner and the loser when the loser finishes the race.
Distance between the winner and the loser = $$330 \, \text{m} - (281.25 \, \text{m} + 5.5 \, \text{m}) = 43.25 \, \text{m}$$

Therefore, the winner will be 43.25 meters ahead of the loser when the loser finishes the race.