Quadrilateral JKLM with vertices J(0,12),K(8,12),L(4,0) and M(-8,4):k=1/4 rd K'(square , L(square ,square M'(

To find the coordinates of the vertices of the quadrilateral after applying the dilation with a scale factor of $k = \frac{1}{4}$, we need to multiply the coordinates of each vertex by the scale factor.<br /><br />Given:<br />$J(0,12), K(8,12), L(4,0), M(-8,4)$<br /><br />Step 1: Find the coordinates of $K'$.<br />$K' = (8 \times \frac{1}{4}, 12 \times \frac{1}{4}) = (2,3)$<br /><br />Step 2: Find the coordinates of $L'$.<br />$L' = (4 \times \frac{1}{4}, 0 \times \frac{1}{4}) = (1,0)$<br /><br />Step 3: Find the coordinates of $M'$.<br />$M' = (-8 \times \frac{1}{4}, 4 \times \frac{1}{4}) = (-2,1)$<br /><br />Therefore, the coordinates of the vertices of the quadrilateral after applying the dilation with a scale factor of $\frac{1}{4}$ are:<br />$J'(0,12), K'(2,3), L'(1,0), M'(-2,1)$