Pergunta
1) Calcular as adiçoes e subtrações de fraçōes. a) (2)/(7)+(10)/(7)=(17)/(7) 5+(3)/(5)+(8)/(10)=5(1)/(30) b) 4(5)/(9)-(3)/(9)=4(2)/(9) f) 10-(7)/(4)-(5)/(6)= C 5(1)/(2)+(2)/(3)=5(7)/(6) g) (1)/(4)+6(2)/(3)+(5)/(6)= d) (5)/(3)-(3)/(4)=(16)/(12) h) 5(2)/(5)-(1)/(3)+(1)/(2)= 2) Compare as frações. a) 3(2)/(7) e (10)/(7)Longrightarrow (5)/(9) e (3)/(9)Longrightarrow 3) Simplifique as frações abaixo. a) (10)/(18)= b) (6)/(14)=
Solução
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AndréElite · Tutor por 8 anos
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1) Calcular as adições e subtrações de frações:<br /><br />a) $\frac{2}{7} + \frac{10}{7} = \frac{12}{7}$<br /><br />b) $4\frac{5}{9} - \frac{3}{9} = 4\frac{2}{9}$<br /><br />c) $10 - \frac{7}{4} - \frac{5}{6} = 10 - 1.75 - 0.8333 = 7.4167$<br /><br />d) $\frac{5}{3} - \frac{3}{4} = \frac{20}{12} - \frac{9}{12} = \frac{11}{12}$<br /><br />e) $5\frac{1}{2} + \frac{2}{3} = 5\frac{3}{6} + \frac{4}{6} = 5\frac{7}{6}$<br /><br />f) $\frac{1}{4} + 6\frac{2}{3} + \frac{5}{6} = \frac{3}{12} + \frac{24}{3} + \frac{10}{6} = \frac{3}{12} + 8 + \frac{10}{6} = \frac{3}{12} + 8 + \frac{20}{12} = 8\frac{23}{12}$<br /><br />g) $5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{3}{6} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3} + \frac{1}{2} = 5\frac{2}{5} - \frac{1}{3}
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