Um móvel realiza um movimento uniforme num determinado referencial. Seus espaços variam com o tempo segundo os dados da tabela. Qual será a função horária do movimento uniforme realizado e a que posição será o móvel depois de 2 minutos? mathbf(t)(mathbf(s)) & mathbf(0) & mathbf(2) & mathbf(4) & mathbf(6) & mathbf(8) & mathbf(1 0) mathbf(d)(mathbf(m)) & 40 & 80 & 120 & 160 & 200 & 240 Múltipla Escolha: A. mathrm(d)=40+20 mathrm(t) é mathrm(d)=1,24 mathrm(~km) . B. mathrm(d)=40+20 mathrm(t) é mathrm(d)=80 mathrm(~m) . C. mathrm(d)=20+40 mathrm(t) é mathrm(d)=2,42 mathrm(~km) . D. mathrm(d)=40+20 mathrm(t) é mathrm(d)=2,44 mathrm(~km) . E. mathrm(d)=20+40 mathrm(t) é mathrm(d)=4,82 mathrm(~km) .

## Step 1: Determine the Uniform Motion Equation<br />### The table provides data for time \( t \) in seconds and distance \( d \) in meters. We observe that as time increases by 2 seconds, the distance increases by 40 meters. This indicates a uniform motion with constant velocity. The general equation for uniform motion is \( d = d_0 + vt \), where \( d_0 \) is the initial position and \( v \) is the velocity.<br />### From the table, at \( t = 0 \), \( d = 40 \). Therefore, \( d_0 = 40 \).<br />### To find the velocity \( v \), we use two points from the table: when \( t = 0 \), \( d = 40 \) and when \( t = 2 \), \( d = 80 \). Thus, the change in distance is \( 80 - 40 = 40 \) meters over 2 seconds, giving a velocity \( v = \frac{40}{2} = 20 \) m/s.<br />### Therefore, the function for the uniform motion is \( d(t) = 40 + 20t \).<br /><br />## Step 2: Calculate the Position After 2 Minutes<br />### Convert 2 minutes into seconds: \( 2 \times 60 = 120 \) seconds.<br />### Substitute \( t = 120 \) into the equation \( d(t) = 40 + 20t \):<br />\[<br />d(120) = 40 + 20 \times 120 = 40 + 2400 = 2440 \text{ meters}<br />\]<br /><br />## Step 3: Match the Calculated Position to the Multiple Choice Options<br />### The calculated position after 2 minutes (120 seconds) is 2440 meters or 2.44 kilometers. <br />### Among the options provided, option D matches this result.