1 F=50N a=10m/s^2 Find m. 2 F=1250N a=3.68m/s^2 Find m. 3. m=660kg a=0.25m/s^2 Find F. 4 F=900N m=60kg Find

Let's solve each of the problems step-by-step using Newton's second law of motion, which states that the force \( F \) acting on an object is equal to the mass \( m \) of the object multiplied by its acceleration \( a \). The formula is:<br /><br />\[ F = m \cdot a \]<br /><br />### Problem 1<br />Given:<br />- \( F = 50 \, \text{N} \)<br />- \( a = 10 \, \text{m/s}^2 \)<br /><br />Find \( m \):<br /><br />\[ m = \frac{F}{a} = \frac{50 \, \text{N}}{10 \, \text{m/s}^2} = 5 \, \text{kg} \]<br /><br />### Problem 2<br />Given:<br />- \( F = 1250 \, \text{N} \)<br />- \( a = 3.68 \, \text{m/s}^2 \)<br /><br />Find \( m \):<br /><br />\[ m = \frac{F}{a} = \frac{1250 \, \text{N}}{3.68 \, \text{m/s}^2} \approx 338.24 \, \text{kg} \]<br /><br />### Problem 3<br />Given:<br />- \( m = 660 \, \text{kg} \)<br />- \( a = 0.25 \, \text{m/s}^2 \)<br /><br />Find \( F \):<br /><br />\[ F = m \cdot a = 660 \, \text{kg} \times 0.25 \, \text{m/s}^2 = 165 \, \text{N} \]<br /><br />### Problem 4<br />Given:<br />- \( F = 900 \, \text{N} \)<br />- \( m = 60 \, \text{kg} \)<br /><br />Find \( a \):<br /><br />\[ a = \frac{F}{m} = \frac{900 \, \text{N}}{60 \, \text{kg}} = 15 \, \text{m/s}^2 \]<br /><br />### Summary of Solutions<br />1. \( m = 5 \, \text{kg} \)<br />2. \( m \approx 338.24 \, \text{kg} \)<br />3. \( F = 165 \, \text{N} \)<br />4. \( a = 15 \, \text{m/s}^2 \)