Solve using substitution. -8x+10y=6 6x-2y=-10 square square politician D

To solve the system of equations using substitution, we first solve one equation for one variable and then substitute that expression into the other equation.

From the second equation, we can solve for $$x$$ :
$$6x - 2y = -10$$
$$6x = 2y - 10$$
$$x = \frac{1}{3}y - \frac{5}{3}$$

Now we substitute this expression for $$x$$ into the first equation:
$$-8x + 10y = 6$$
$$-8(\frac{1}{3}y - \frac{5}{3}) + 10y = 6$$
$$-\frac{8}{3}y + \frac{40}{3} + 10y = 6$$
$$\frac{22}{3}y + \frac{40}{3} = 6$$
$$\frac{22}{3}y = 6 - \frac{40}{3}$$
$$\frac{22}{3}y = \frac{18}{3} - \frac{40}{3}$$
$$\frac{22}{3}y = -\frac{22}{3}$$
$$y = -1$$

Now that we have the value of $$y$$ , we can substitute it back into the expression for $$x$$ :
$$x = \frac{1}{3}y - \frac{5}{3}$$
$$x = \frac{1}{3}(-1) - \frac{5}{3}$$
$$x = -\frac{1}{3} - \frac{5}{3}$$
$$x = -2$$

Therefore, the solution to the system of equations is $$x = -2$$ and $$y = -1$$ .